Abitur · 12% of test plan
Mathematik — Analysis (Calculus) for the Abitur Exam
Analysis is the largest topic in Abitur Mathematik, covering approximately 50% of the examination across all German states. It includes differentiation (including product, quotient, and chain rules), integration (definite and indefinite), curve sketching, and applied problems (Extremwertaufgaben/optimisation).
Locale-specific study guides
Pass-rate data, regulatory context, and study tips for Mathematik — Analysis (Calculus) all change by candidate locale. Pick your context:
- Mathematik — Analysis (Calculus) · United StatesCalibrated for American candidates
- Mathematik — Analysis (Calculus) · United KingdomCalibrated for British candidates
- Mathematik — Analysis (Calculus) · IndiaCalibrated for Indian candidates
- Mathematik — Analysis (Calculus) · PhilippinesCalibrated for Filipino candidates
- Mathematik — Analysis (Calculus) · NigeriaCalibrated for Nigerian candidates
Common failure modes
These are the patterns that cause most candidates to lose marks on this topic. Recognising them in advance is half the work.
- !Forgetting to apply the chain rule when differentiating composite functions
- !Integration errors: missing the constant of integration, or incorrect limits for definite integrals
- !Not showing the complete Kurvendiskussion (function analysis) steps: domain, zeros, extrema, inflection points, asymptotes
Study tips
- 1Master all six differentiation rules: Ableitungsregel for power, product (Produktregel), quotient (Quotientenregel), chain (Kettenregel), sum, and constant-factor rule.
- 2Practise the complete Kurvendiskussion (function analysis) template: Definitionsbereich → Nullstellen → Extremstellen → Wendepunkte → Verhalten für x → ±∞.
- 3For Extremwertaufgaben (optimisation): define the objective function, find the domain, differentiate, set to zero, verify it is a maximum/minimum.
Sample Abitur Mathematik — Analysis (Calculus) questions
These sample items mirror the format and difficulty of real Abitur questions. Practice with thousands more on the free Koydo question bank.
- 1
Gegeben: f(x) = x³ − 3x. Bestimmen Sie die Extremstellen. (Given: f(x) = x³ − 3x. Find the extrema.)
- AKeine Extremstellen (No extrema)
- BMinimum bei x = 0
- CMaximum bei x = −1, Minimum bei x = 1Correct
- DMaximum bei x = 1, Minimum bei x = −1
Why this answer?
f'(x) = 3x² − 3 = 0 → x² = 1 → x = ±1. f''(x) = 6x. At x = −1: f''(−1) = −6 < 0 → Hochpunkt (maximum). At x = 1: f''(1) = 6 > 0 → Tiefpunkt (minimum). Maxima at x = −1, Minima at x = 1.
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