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Mathematik — Analysis (Calculus) for the Abitur Exam

Analysis is the largest topic in Abitur Mathematik, covering approximately 50% of the examination across all German states. It includes differentiation (including product, quotient, and chain rules), integration (definite and indefinite), curve sketching, and applied problems (Extremwertaufgaben/optimisation).

Locale-specific study guides

Pass-rate data, regulatory context, and study tips for Mathematik — Analysis (Calculus) all change by candidate locale. Pick your context:

Common failure modes

These are the patterns that cause most candidates to lose marks on this topic. Recognising them in advance is half the work.

  • !Forgetting to apply the chain rule when differentiating composite functions
  • !Integration errors: missing the constant of integration, or incorrect limits for definite integrals
  • !Not showing the complete Kurvendiskussion (function analysis) steps: domain, zeros, extrema, inflection points, asymptotes

Study tips

  • 1Master all six differentiation rules: Ableitungsregel for power, product (Produktregel), quotient (Quotientenregel), chain (Kettenregel), sum, and constant-factor rule.
  • 2Practise the complete Kurvendiskussion (function analysis) template: Definitionsbereich → Nullstellen → Extremstellen → Wendepunkte → Verhalten für x → ±∞.
  • 3For Extremwertaufgaben (optimisation): define the objective function, find the domain, differentiate, set to zero, verify it is a maximum/minimum.

Sample Abitur Mathematik — Analysis (Calculus) questions

These sample items mirror the format and difficulty of real Abitur questions. Practice with thousands more on the free Koydo question bank.

  1. 1

    Gegeben: f(x) = x³ − 3x. Bestimmen Sie die Extremstellen. (Given: f(x) = x³ − 3x. Find the extrema.)

    • AKeine Extremstellen (No extrema)
    • BMinimum bei x = 0
    • CMaximum bei x = −1, Minimum bei x = 1Correct
    • DMaximum bei x = 1, Minimum bei x = −1
    Why this answer?

    f'(x) = 3x² − 3 = 0 → x² = 1 → x = ±1. f''(x) = 6x. At x = −1: f''(−1) = −6 < 0 → Hochpunkt (maximum). At x = 1: f''(1) = 6 > 0 → Tiefpunkt (minimum). Maxima at x = −1, Minima at x = 1.

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