Chemistry — Physical Chemistry for the JEE Main Exam — Luzon candidates

Common failure modes

These are the patterns that cause most candidates to lose marks on this topic. Recognising them in advance is half the work.

• !Confusing ΔG with ΔG° — forgetting the Q (reaction quotient) term in ΔG = ΔG° + RT ln Q
• !Misapplying the Nernst equation when concentrations are non-standard
• !Using first-order half-life formula for a second-order reaction
• !Forgetting to convert temperature to Kelvin in Arrhenius and thermodynamic equations
• !Misidentifying buffer problems — Henderson-Hasselbalch requires a weak acid and its conjugate base, not any two acids

Study tips

• 1Build a formula card for physical chemistry: ΔG = ΔH − TΔS, Nernst equation, Arrhenius equation, Van't Hoff factor, and Raoult's law. JEE Main is formula-driven here.
• 2Practice electrochemistry cell-notation reading — JEE routinely asks cell EMF from given half-reactions.
• 3Drill rate-law problems by order determination from experimental data (method of initial rates).
• 4For solutions, practice colligative property calculations: depression of freezing point, elevation of boiling point, osmotic pressure.
• 5Do at least 5 past-paper thermodynamics questions per sitting — the multi-step Hess's law + entropy problems are high-value.
• 6For NCLEX-RN: the Pearson VUE Manila centre is the only PH NCLEX site — book 6–8 weeks in advance, especially Q1 (post-graduation surge).
• 7CGFNS CES is mandatory for U.S. board endorsement of Filipino nursing credentials — start the application the same week you confirm your NCLEX ATT.
• 8For IELTS: British Council and IDP both run multiple weekly sessions in Manila. Speaking-test slots in Makati and Pasig fill first; book a Quezon City slot if you can travel.

Sample JEE Main Chemistry — Physical Chemistry questions

These sample items mirror the format and difficulty of real JEE Main questions. Practice with thousands more on the free Koydo question bank.

1. 1

   For a reaction at equilibrium at 298 K, if ΔG° = −5.7 kJ/mol, the equilibrium constant K is approximately (R = 8.314 J/mol·K):

   • A10Correct
   • B100
   • C1000
   • D0.1
   Why this answer?

   Illustrative JEE-style: ΔG° = −RT ln K, so ln K = −ΔG°/(RT) = 5700/(8.314 × 298) ≈ 2.30, giving K ≈ e^2.30 ≈ 10.

2. 2

   For a first-order reaction, the time required for 75% completion is:

   • At½
   • B2t½Correct
   • C3t½
   • D4t½
   Why this answer?

   Illustrative JEE-style: At 75% completion, 25% remains. Using N = N₀(1/2)^n, 0.25 = (1/2)^n gives n = 2. So time = 2t½.

3. 3

   Electrolysis of water produces hydrogen and oxygen in a volume ratio of:

   • A1 : 1
   • B2 : 1Correct
   • C1 : 2
   • D4 : 1
   Why this answer?

   Illustrative JEE-style: 2H₂O → 2H₂ + O₂. At the same temperature and pressure, volumes are proportional to moles, giving H₂ : O₂ = 2 : 1.

Frequently asked questions

Related study guides

• Physics — Mechanics for JEE Main (Luzon, Philippines)Another JEE Main topic for Luzon-based Filipino candidates
• Physics — Electromagnetism for JEE Main (Luzon, Philippines)Another JEE Main topic for Luzon-based Filipino candidates
• Physics — Modern Physics for JEE Main (Luzon, Philippines)Another JEE Main topic for Luzon-based Filipino candidates
• Chemistry — Inorganic Chemistry for JEE Main (Luzon, Philippines)Another JEE Main topic for Luzon-based Filipino candidates
• Chemistry — Organic Chemistry for JEE Main (Luzon, Philippines)Another JEE Main topic for Luzon-based Filipino candidates
• Chemistry — Physical Chemistry for JEE Main — U.S. candidatesSame Chemistry — Physical Chemistry topic, different locale framing
• Chemistry — Physical Chemistry for JEE Main — U.K. candidatesSame Chemistry — Physical Chemistry topic, different locale framing
• Chemistry — Physical Chemistry for JEE Main — Indian candidatesSame Chemistry — Physical Chemistry topic, different locale framing