JEE Main · Physics — Modern Physics · Maharashtra, India
Physics — Modern Physics for the JEE Main Exam — Maharashtra candidates
5% of the JEE Main test plan. Photoelectric effect, nuclear physics, atomic models, dual nature of matter, and semiconductors — about 15% of JEE Physics. Calibrated for Maharashtrian candidates.
Behind every published pass rate is a distribution of which topics caused most of the failures. This is one of those topics. Physics — Modern Physics sits at roughly 5% of the Joint Entrance Examination Main content distribution — Modern Physics is the most formula-dense topic in JEE Physics and the area where students recover marks lost in mechanics and E&M. Photoelectric effect and nuclear decay are almost guaranteed to appear in JEE Main. JEE Advanced includes Bohr model derivations and semiconductor band theory. Pass rates for the JEE Main are published annually by the awarding body and vary by cohort and locale. For Maharashtra candidates preparing for JEE Main, the calibration of study to local context matters: Maharashtra hosts the largest single-state JEE Main, NEET, and CET cohorts in India. MHT-CET is the state-level entrance test; many candidates sit JEE Main, MHT-CET, and NEET in the same year.
Common failure modes
These are the patterns that cause most candidates to lose marks on this topic. Recognising them in advance is half the work.
- !Confusing threshold frequency with work function (φ = hν₀, not hν₀/e)
- !Applying Einstein's photoelectric equation without subtracting the work function
- !Misidentifying the nuclear binding energy trend — iron-56 is the most stable, not the lightest or heaviest nucleus
- !Forgetting de Broglie wavelength depends on momentum, not speed, when the particle is relativistic
- !Mixing up NPN and PNP transistor biasing configurations
Study tips
- 1Memorise Planck's constant (h = 6.626 × 10⁻³⁴ J·s) and the eV–joule conversion (1 eV = 1.6 × 10⁻¹⁹ J) — both are used in almost every modern-physics calculation.
- 2Drill Bohr model energy levels for hydrogen: Eₙ = −13.6/n² eV. JEE Main frequently asks about energy transitions.
- 3Practice half-life problems with the formula N(t) = N₀(1/2)^(t/T½) — variants appear every year.
- 4For semiconductors, understand intrinsic vs extrinsic (n-type, p-type) and the forward-bias vs reverse-bias I-V curve.
- 5Work through at least one paper-year of photoelectric problems to internalise the Einstein equation and the stopping-potential concept.
- 6JEE Main and NEET are offered in Marathi (मराठी) at all Maharashtra centres — choose the medium that matches your school instruction medium for best comprehension speed.
- 7For NEET: Maharashtra State CET Cell runs separate state-quota counselling alongside MCC all-India counselling — register for both to maximise admission chances.
- 8Mumbai and Pune are the highest-density centres; book test slots within 30 minutes of your home pin code to avoid Mumbai monsoon-season transit delays on test day.
Sample JEE Main Physics — Modern Physics questions
These sample items mirror the format and difficulty of real JEE Main questions. Practice with thousands more on the free Koydo question bank.
- 1
In the photoelectric effect, the stopping potential depends on:
- AIntensity of incident light only
- BFrequency of incident light onlyCorrect
- CBoth intensity and frequency
- DNeither intensity nor frequency
Why this answer?
Illustrative JEE-style: Einstein's photoelectric equation gives KE_max = hν − φ = eV_stop. The stopping potential V_stop depends only on the frequency ν of the incident light, not on its intensity. Higher intensity increases the number of photoelectrons but not their maximum energy.
- 2
A radioactive sample has a half-life of 5 years. After 15 years, the fraction remaining is:
- A1/8Correct
- B1/4
- C1/3
- D1/16
Why this answer?
Illustrative JEE-style: 15 years = 3 half-lives. The fraction remaining = (1/2)³ = 1/8.
- 3
The de Broglie wavelength of an electron accelerated through a potential difference V is proportional to:
- AV
- B1/√VCorrect
- C√V
- D1/V
Why this answer?
Illustrative JEE-style: KE = eV, so momentum p = √(2meV). de Broglie wavelength λ = h/p = h/√(2meV) ∝ 1/√V.
Frequently asked questions
How many marks does Modern Physics typically carry in JEE Main?
Is semiconductors a reliable scoring topic?
What is the JEE Main pass rate for Maharashtrian candidates?
How long should Maharashtrian candidates study Physics — Modern Physics for the JEE Main?
Practice JEE Main free with Koydo.
PCM full-length tests, NTA-aligned, with previous-year drill sets.
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Regulatory citation: NTA JEE Main Information Bulletin — Physics syllabus (Dual Nature of Radiation and Matter, Atoms, Nuclei, Electronic Devices).